Eternity Async Tutoring

[Eternity]

@Elliot

Does your solution rely on negative numbers or could you just add 2 so it deals with positives so you don’t have to worry about mod/remainder weirdness? In other words, would the below work? You tell me.

(x-y+2) remainder 2

It does rely on negative numbers. Let’s see
(0-0+2) remainder 2 = 0
(1-0+2) remainder 2 = 1 + 2 remainder 2 = 3 remainder 2 = 1
(0-1+2) remainder 2 = -1 + 2 remainder 2 = 1 remainder 2 = 1
(1-1+2) remainder 2 = 0 + 2 remainder 2 = 2 remainder 2 = 0

Hmm. Yeah I could’ve added two and not dealt with negative numbers.

@Elliot

take x+y, x+y+1 or x*y as one thing and then add, subtract or multiply it with a second thing. The second thing could be using remainder 2 on any of the first things. Doing this, you should either be able to find a solution or find something that seems useful which has some advantage over your starting place which could reach a solution using further operations.

or(x,y) = (x+y+xy) remainder 2
or(0,0) = (0+0+0) remainder 2 = 0
or(1,0) = (1+0+0) remainder 2 = 1
or(0,1) = (0+1+0) remainder 2 = 1
or(1,1) = (1+1+1) remainder 2 = 3 remainder 2 = 1